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Can you integrate this?
Created 25th May 2014 @ 15:10
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Sin (pi/2) * cos (x)
Hodor.
Use euler’s identity e^(ix) = cosx + isinx to solve it?
Quoted from octane
http://integrals.wolfram.com/index.jsp?expr=Sin%28pi%2F2%29+cos%28x%29&random=false
Thanks I know the answer…
That doesn’t show where it came from
sin (pi/2) is just a constant
edit: so you’re just integrating cos(x)
Last edited by Starkie,
I see. Could you explain a little further, please?
Why doesn’t it affect the cos at all?
Last edited by jx53,
do your own homework
Quoted from yak
do your own homework
I am.
Sin (pi/2) = 1
So Sin (pi/2) * cos(x) = cos(x)
Integral of cos(x) = sin(x) + c
Sin(pi/2) (assuming this is in radians) is the same as sin(90) (aka 1).
Therefore it’s just ∫cos(x) dx, which is simply sin(x) + c.
sin(pi/2) can be taken out of the integral since it’s a constant (it’s 1)
and the integral of cos(x)=sin(x)+c
so the answer is simply sin(x)+c
excuse me i’m a professional mathematician here, don’t trump me
Last edited by Permzilla,
Quoted from Rex
Sin (pi/2) = 1
So Sin (pi/2) * cos(x) = cos(x)
Integral of cos(x) = sin(x) + c
Sin pi/2 shows as 0.2741213359 to me
Quoted from jx53
[…]
Sin pi/2 shows as 0.2741213359 to me
make sure your calculator is in radians, or alternatively put sin(90) in since pi= 180 degrees
Last edited by Permzilla,
Yeah. But what if it is sin (3.14/2)
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